27y^2-52y+25=0

Solution for 27y^2-52y+25=0 equation:

Simplifying
27y2 + -52y + 25 = 0

Reorder the terms:
25 + -52y + 27y2 = 0

Solving
25 + -52y + 27y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(25 + -27y)(1 + -1y) = 0

Subproblem 1
Set the factor '(25 + -27y)' equal to zero and attempt to solve:

Simplifying
25 + -27y = 0

Solving
25 + -27y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-25' to each side of the equation.
25 + -25 + -27y = 0 + -25

Combine like terms: 25 + -25 = 0
0 + -27y = 0 + -25
-27y = 0 + -25

Combine like terms: 0 + -25 = -25
-27y = -25

Divide each side by '-27'.
y = 0.9259259259

Simplifying
y = 0.9259259259
Subproblem 2
Set the factor '(1 + -1y)' equal to zero and attempt to solve:

Simplifying
1 + -1y = 0

Solving
1 + -1y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1y = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1y = 0 + -1
-1y = 0 + -1

Combine like terms: 0 + -1 = -1
-1y = -1

Divide each side by '-1'.
y = 1

Simplifying
y = 1
Solution
y = {0.9259259259, 1}